Optimal. Leaf size=150 \[ \frac {244 \sin (c+d x)}{105 a^4 d}-\frac {88 \sin (c+d x) \cos ^2(c+d x)}{105 a^4 d (\cos (c+d x)+1)^2}+\frac {4 \sin (c+d x)}{a^4 d (\cos (c+d x)+1)}-\frac {4 x}{a^4}-\frac {\sin (c+d x) \cos ^4(c+d x)}{7 d (a \cos (c+d x)+a)^4}-\frac {12 \sin (c+d x) \cos ^3(c+d x)}{35 a d (a \cos (c+d x)+a)^3} \]
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Rubi [A] time = 0.37, antiderivative size = 150, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {2765, 2977, 2968, 3023, 12, 2735, 2648} \[ \frac {244 \sin (c+d x)}{105 a^4 d}-\frac {88 \sin (c+d x) \cos ^2(c+d x)}{105 a^4 d (\cos (c+d x)+1)^2}+\frac {4 \sin (c+d x)}{a^4 d (\cos (c+d x)+1)}-\frac {4 x}{a^4}-\frac {\sin (c+d x) \cos ^4(c+d x)}{7 d (a \cos (c+d x)+a)^4}-\frac {12 \sin (c+d x) \cos ^3(c+d x)}{35 a d (a \cos (c+d x)+a)^3} \]
Antiderivative was successfully verified.
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Rule 12
Rule 2648
Rule 2735
Rule 2765
Rule 2968
Rule 2977
Rule 3023
Rubi steps
\begin {align*} \int \frac {\cos ^5(c+d x)}{(a+a \cos (c+d x))^4} \, dx &=-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {\int \frac {\cos ^3(c+d x) (4 a-8 a \cos (c+d x))}{(a+a \cos (c+d x))^3} \, dx}{7 a^2}\\ &=-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {12 \cos ^3(c+d x) \sin (c+d x)}{35 a d (a+a \cos (c+d x))^3}-\frac {\int \frac {\cos ^2(c+d x) \left (36 a^2-52 a^2 \cos (c+d x)\right )}{(a+a \cos (c+d x))^2} \, dx}{35 a^4}\\ &=-\frac {88 \cos ^2(c+d x) \sin (c+d x)}{105 a^4 d (1+\cos (c+d x))^2}-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {12 \cos ^3(c+d x) \sin (c+d x)}{35 a d (a+a \cos (c+d x))^3}-\frac {\int \frac {\cos (c+d x) \left (176 a^3-244 a^3 \cos (c+d x)\right )}{a+a \cos (c+d x)} \, dx}{105 a^6}\\ &=-\frac {88 \cos ^2(c+d x) \sin (c+d x)}{105 a^4 d (1+\cos (c+d x))^2}-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {12 \cos ^3(c+d x) \sin (c+d x)}{35 a d (a+a \cos (c+d x))^3}-\frac {\int \frac {176 a^3 \cos (c+d x)-244 a^3 \cos ^2(c+d x)}{a+a \cos (c+d x)} \, dx}{105 a^6}\\ &=\frac {244 \sin (c+d x)}{105 a^4 d}-\frac {88 \cos ^2(c+d x) \sin (c+d x)}{105 a^4 d (1+\cos (c+d x))^2}-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {12 \cos ^3(c+d x) \sin (c+d x)}{35 a d (a+a \cos (c+d x))^3}-\frac {\int \frac {420 a^4 \cos (c+d x)}{a+a \cos (c+d x)} \, dx}{105 a^7}\\ &=\frac {244 \sin (c+d x)}{105 a^4 d}-\frac {88 \cos ^2(c+d x) \sin (c+d x)}{105 a^4 d (1+\cos (c+d x))^2}-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {12 \cos ^3(c+d x) \sin (c+d x)}{35 a d (a+a \cos (c+d x))^3}-\frac {4 \int \frac {\cos (c+d x)}{a+a \cos (c+d x)} \, dx}{a^3}\\ &=-\frac {4 x}{a^4}+\frac {244 \sin (c+d x)}{105 a^4 d}-\frac {88 \cos ^2(c+d x) \sin (c+d x)}{105 a^4 d (1+\cos (c+d x))^2}-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {12 \cos ^3(c+d x) \sin (c+d x)}{35 a d (a+a \cos (c+d x))^3}+\frac {4 \int \frac {1}{a+a \cos (c+d x)} \, dx}{a^3}\\ &=-\frac {4 x}{a^4}+\frac {244 \sin (c+d x)}{105 a^4 d}-\frac {88 \cos ^2(c+d x) \sin (c+d x)}{105 a^4 d (1+\cos (c+d x))^2}-\frac {\cos ^4(c+d x) \sin (c+d x)}{7 d (a+a \cos (c+d x))^4}-\frac {12 \cos ^3(c+d x) \sin (c+d x)}{35 a d (a+a \cos (c+d x))^3}+\frac {4 \sin (c+d x)}{d \left (a^4+a^4 \cos (c+d x)\right )}\\ \end {align*}
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Mathematica [A] time = 0.42, size = 263, normalized size = 1.75 \[ -\frac {\sec \left (\frac {c}{2}\right ) \sec ^7\left (\frac {1}{2} (c+d x)\right ) \left (46130 \sin \left (c+\frac {d x}{2}\right )-46116 \sin \left (c+\frac {3 d x}{2}\right )+18060 \sin \left (2 c+\frac {3 d x}{2}\right )-19292 \sin \left (2 c+\frac {5 d x}{2}\right )+2100 \sin \left (3 c+\frac {5 d x}{2}\right )-3791 \sin \left (3 c+\frac {7 d x}{2}\right )-735 \sin \left (4 c+\frac {7 d x}{2}\right )-105 \sin \left (4 c+\frac {9 d x}{2}\right )-105 \sin \left (5 c+\frac {9 d x}{2}\right )+29400 d x \cos \left (c+\frac {d x}{2}\right )+17640 d x \cos \left (c+\frac {3 d x}{2}\right )+17640 d x \cos \left (2 c+\frac {3 d x}{2}\right )+5880 d x \cos \left (2 c+\frac {5 d x}{2}\right )+5880 d x \cos \left (3 c+\frac {5 d x}{2}\right )+840 d x \cos \left (3 c+\frac {7 d x}{2}\right )+840 d x \cos \left (4 c+\frac {7 d x}{2}\right )-60830 \sin \left (\frac {d x}{2}\right )+29400 d x \cos \left (\frac {d x}{2}\right )\right )}{26880 a^4 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.65, size = 162, normalized size = 1.08 \[ -\frac {420 \, d x \cos \left (d x + c\right )^{4} + 1680 \, d x \cos \left (d x + c\right )^{3} + 2520 \, d x \cos \left (d x + c\right )^{2} + 1680 \, d x \cos \left (d x + c\right ) + 420 \, d x - {\left (105 \, \cos \left (d x + c\right )^{4} + 1184 \, \cos \left (d x + c\right )^{3} + 2636 \, \cos \left (d x + c\right )^{2} + 2236 \, \cos \left (d x + c\right ) + 664\right )} \sin \left (d x + c\right )}{105 \, {\left (a^{4} d \cos \left (d x + c\right )^{4} + 4 \, a^{4} d \cos \left (d x + c\right )^{3} + 6 \, a^{4} d \cos \left (d x + c\right )^{2} + 4 \, a^{4} d \cos \left (d x + c\right ) + a^{4} d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.49, size = 112, normalized size = 0.75 \[ -\frac {\frac {3360 \, {\left (d x + c\right )}}{a^{4}} - \frac {1680 \, \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} + 1\right )} a^{4}} + \frac {15 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 147 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 805 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 5145 \, a^{24} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )}{a^{28}}}{840 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.06, size = 126, normalized size = 0.84 \[ -\frac {\tan ^{7}\left (\frac {d x}{2}+\frac {c}{2}\right )}{56 d \,a^{4}}+\frac {7 \left (\tan ^{5}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{40 d \,a^{4}}-\frac {23 \left (\tan ^{3}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{24 d \,a^{4}}+\frac {49 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{8 d \,a^{4}}+\frac {2 \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d \,a^{4} \left (1+\tan ^{2}\left (\frac {d x}{2}+\frac {c}{2}\right )\right )}-\frac {8 \arctan \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )\right )}{d \,a^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.81, size = 158, normalized size = 1.05 \[ \frac {\frac {1680 \, \sin \left (d x + c\right )}{{\left (a^{4} + \frac {a^{4} \sin \left (d x + c\right )^{2}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{2}}\right )} {\left (\cos \left (d x + c\right ) + 1\right )}} + \frac {\frac {5145 \, \sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1} - \frac {805 \, \sin \left (d x + c\right )^{3}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{3}} + \frac {147 \, \sin \left (d x + c\right )^{5}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{5}} - \frac {15 \, \sin \left (d x + c\right )^{7}}{{\left (\cos \left (d x + c\right ) + 1\right )}^{7}}}{a^{4}} - \frac {6720 \, \arctan \left (\frac {\sin \left (d x + c\right )}{\cos \left (d x + c\right ) + 1}\right )}{a^{4}}}{840 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.47, size = 137, normalized size = 0.91 \[ -\frac {15\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-192\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^2\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )+1144\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^4\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-6112\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^6\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )-1680\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^8\,\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )+3360\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7\,\left (c+d\,x\right )}{840\,a^4\,d\,{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}^7} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 19.07, size = 280, normalized size = 1.87 \[ \begin {cases} - \frac {3360 d x \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{840 a^{4} d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 840 a^{4} d} - \frac {3360 d x}{840 a^{4} d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 840 a^{4} d} - \frac {15 \tan ^{9}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{840 a^{4} d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 840 a^{4} d} + \frac {132 \tan ^{7}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{840 a^{4} d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 840 a^{4} d} - \frac {658 \tan ^{5}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{840 a^{4} d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 840 a^{4} d} + \frac {4340 \tan ^{3}{\left (\frac {c}{2} + \frac {d x}{2} \right )}}{840 a^{4} d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 840 a^{4} d} + \frac {6825 \tan {\left (\frac {c}{2} + \frac {d x}{2} \right )}}{840 a^{4} d \tan ^{2}{\left (\frac {c}{2} + \frac {d x}{2} \right )} + 840 a^{4} d} & \text {for}\: d \neq 0 \\\frac {x \cos ^{5}{\relax (c )}}{\left (a \cos {\relax (c )} + a\right )^{4}} & \text {otherwise} \end {cases} \]
Verification of antiderivative is not currently implemented for this CAS.
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